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5a^2-15a-20=0
a = 5; b = -15; c = -20;
Δ = b2-4ac
Δ = -152-4·5·(-20)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-25}{2*5}=\frac{-10}{10} =-1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+25}{2*5}=\frac{40}{10} =4 $
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